Question # Let n=16+ VII + 16-V11 - 22, then
(A) n21 (B) 0

# Let n=16+ VII + 16-V11 - 22, then
(A) n21 (B) 0

Solution ( n+sqrt{2} 2=sqrt{b+sqrt{u}}+sqrt{b-sqrt{11}} )
( (n+sqrt{2} 2)^{2}=6+sqrt{11}+b-sqrt{11}+2 sqrt{b+sqrt{11}} sqrt{b-sqrt{11}} )
( n^{2}+22+2 sqrt{2} 2 n=12+2(sqrt{3-11})=12+2(5)=22 )
( n^{2}+2 sqrt{2} 2 n=0 )
( therefore[n=0 )

Solution