Let n=16+ VII + 16-V11 - 22, then (...
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Let n=16+ VII + 16-V11 - 22, then (A) n21 (B) 0
JEE/Engineering Exams
Maths
Solution
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( n+sqrt{2} 2=sqrt{b+sqrt{u}}+sqrt{b-sqrt{11}} ) ( (n+sqrt{2} 2)^{2}=6+sqrt{11}+b-sqrt{11}+2 sqrt{b+sqrt{11}} sqrt{b-sqrt{11}} ) ( n^{2}+22+2 sqrt{2} 2 n=12+2(sqrt{3-11})=12+2(5)=22 ) ( n^{2}+2 sqrt{2} 2 n=0 ) ( therefore[n=0 )

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