Letf(x) = log (sin x), (0

JEE/Engineering Exams

Maths

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[ f(x)=log _{e}(ln 17) cdot(00) ) ( a=left(f(0,9)^{prime}(alpha), l, b=(text { fug })(alpha)right. ) ( operatorname{fog}(x)=log _{e}[lim [lim (e-4)] ) ( operatorname{fog}(x)=log _{e} e^{-x} ) ( operatorname{fog}(x)=-x cdot Rightarrow operatorname{fog}(alpha)=-alpha ) ( f(x)=-1 Rightarrow(operatorname{fog})^{prime}(alpha)=-1 ) The ( b=-alpha . ) [ f quad a=-1 ] foom oblim ( a alpha^{2}-b alpha-a=1 ) ( tan ^{2}-b alpha-a ) ( -x^{2}+x^{2}+1=1=R 4 S ) So, option ( b ) is cossrect Pleaye give your feedback 9306109678

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