Question

( begin{aligned} gamma(e)=& e^{136}+e^{136}-9^{136}+1 quadleft(begin{array}{ll}text { by } & text { comaind } text { theom } )end{array}right. &=e^{13} begin{array}{ll}+1 & text { Aus. }end{array} end{aligned} )

# Letr(x) is remainder, when polynomial P(x) = e.x135 + ell.x125 - el.x115 - e!3 x + 1 is divided by xi-e x, then the value of r(e) is [Note: e denotes Napier's constant]

Solution