Question

It is given that the two metals are present in equal amounts, then
( W_{M g}=W_{T i} )
or ( frac{W_{M g}}{W_{T i}}=frac{n_{M g} times 24}{n_{T i} times 48}=1 )
or ( n_{M g}=2 n_{T i} )
Now, since the number of atoms of Mg and Ti can be present in a whole number ratio, every molecule of protein will contains at least 1 Ti and ( 2 mathrm{Mg} ) atoms.
So, in 1 mole of protein we will have 1 mole of Ti and 2 mole of Mg atoms.
Weight of metal per mole of protein molecule will be ( =48+(2 times 24)=96 mathrm{g} )
If this ( 96 mathrm{g} ) is the ( 0.015 % ) of the molar mass of the protein then,
Molar mass of protein = ( 96 times frac{100}{0.015}=6.4 times 10^{5} g m o l^{-1} )

# Level - 3 144. Exact Duration: A sample of protein was analysed for metal content and analysis reveale, and utanium in equal amounts, by mass. If these are the only metallic species sed for metal content and analysis revealed that it contained magnesium it contains 0.016% metal, by mass, the minimum possible mo lass. If these are the only metallic species present in the protein and netal, by mass, the minimum possible molar mass of the protein is (Mg = 24, Ti = 48) (A) 6, 00, 000 (B) 1. 50, 000 (C) 3. 00, 000 R 12 An non

Solution