Question
( log frac{e^{x}+1}{e^{x}+2}=operatorname{ltg}_{x rightarrow infty} frac{1+e^{-x}}{1+2 e^{-x}} )
( =lim _{x rightarrow infty} frac{1+frac{1}{e^{x}}}{1+frac{2}{e^{x}}} )
( =frac{1+0}{1+0}=1 cdot frac{10 operatorname{tion}(c)}{1-0} )

lime+ *-e is evaluated to be (a) (c) 0 1 (b) (d) - 1 None of these.
Solution
