limit_x→1(1−x+[x−1]+[1−x])= where [...
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( operatorname{limit}_{x rightarrow 1}(1-x+[x-1]+[1-x])= ) where ( [x] ) denotes greatest
integer function
( (a) 0 )
(b) 1
( (c)-1 )
(d) does not exist

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Maths
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limit_x→1(1−x+[x−1]+[1−x])= where [x] denotes greatest integer function
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[
lim _{x rightarrow 1}(1-x+[x-1]+[1-x])
]
( R H L )
[
begin{aligned}
lim _{x rightarrow 1^{+}} &(1-(1+delta x)+[y(1+delta x]+[y-1-delta x])
&=(-8 x+0+-1)=-1
end{aligned}
]
LHL
[
begin{array}{l}
lim _{x rightarrow 1^{-}}(1-(1-delta x)+[1-delta x-1]+[1-(1-delta x)])
quad=(1-1+delta x+[-delta x]+[d x])
quad=0+delta x-1+0=-1
R H L=angle H L=text { finite Nalve }
end{array}
]
limit exist and is equal ( to_{}[-1] )
[
Ans=-1
]

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