Question

( lim _{x rightarrow 0} e^{x} frac{left(e^{tan x-x}-1right)}{(tan x-x)} )
[
begin{array}{ll}text { Fonmula : } frac{e^{x}-1}{x}=1 & (text { Hexe } x=tan x-x) therefore lim _{x rightarrow 0} e^{x}(1) & =e^{0}=1end{array}
]

# Limitetanx - et x+0 tan x - x (a) 1/2 (c)1 (b) 0 (d) none 3* _1

Solution