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log; 6- log} 2 = (logio x - 2) log,...
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log; 6- log} 2 = (logio x - 2) log, 12
JEE/Engineering Exams
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( log 5-lg _{3} 2 ) ( log _{3} 12 ) ( begin{array}{rl}1=log _{10} 2 x-2 . & =log _{20}^{2} x=3 log _{10} x=pm 3 & 10^{2}+2 x_{5} log _{0} 10^{-3}end{array} )
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