Question

[
2 x^{2}-3 x y+y^{2}+x+2 y-8=0
]
So, differentiate
[
begin{array}{l}
4 x-3 y-3 x frac{d y}{d x}+2 y frac{d y}{d x}+1+2 frac{d y}{d x}=0
(2 y-3 x+2) frac{d y}{d x}+4 x-3 y+1=0
(2 y-3 x+2) frac{d y}{d x}=3 y-4 x-1
end{array}
]
[
frac{d y}{d x}=frac{3 y-4 x-1}{2 y-3 x+2}
]
(A) Ans.

# M-II 2018 2x2-3xy + y2 +x+2y=8 = 0 then y 3y - 4x-1 AI 2v-34+2 3y + 4x+1 3) 21+ 3x + 2

Solution