M-II 2018 2x2-3xy + y2 +x+2y=8 = 0 ...
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M-II 2018 2x2-3xy + y2 +x+2y=8 = 0 then y 3y - 4x-1 AI 2v-34+2 3y + 4x+1 3) 21+ 3x + 2

JEE/Engineering Exams
Maths
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[ 2 x^{2}-3 x y+y^{2}+x+2 y-8=0 ] So, differentiate [ begin{array}{l} 4 x-3 y-3 x frac{d y}{d x}+2 y frac{d y}{d x}+1+2 frac{d y}{d x}=0 (2 y-3 x+2) frac{d y}{d x}+4 x-3 y+1=0 (2 y-3 x+2) frac{d y}{d x}=3 y-4 x-1 end{array} ] [ frac{d y}{d x}=frac{3 y-4 x-1}{2 y-3 x+2} ] (A) Ans.
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