Question

(A) oon N to he divisible by 2
Y con take 0,2,4,6,8
And the sum is ( 0+2+4+6+8=20 ).
(B) &on ( N ) to be divisible by 3
3
[
begin{aligned}
1+2+3+x+4+3+y &=text { effe } p(3)
(x+y+1) &=q(3)
end{aligned}
]
[
therefore(x+y) text { can he }, 2,5,8,11,14,17
]
Aud the sum is ( 2+5+8+11+14+17 )
[
=57
]
(c) Fon ( N ) to be divisible by ( b ), Y devould be even , and
[
begin{array}{c}
(x+y+1)=q(3)
y=0,2,4,6,8 text { and }
x(y=0)=2,5,8,
end{array}
]
( x(y=2)=0,3,6,9 )
( x(y=4)=44,7 )
[
x(y=6)=2,5,8
]
( x(x=8)=0,3,6,9 )
Total possibilikes ( =17 )

# Match the column umber N = 123X43 Y where x & y are diaits 0 SX S9 and OSY S 9. Now answer the following (A) If N is divisible by 2, then the sum of all possible () 573 values of y will be (B) If N is divisible by 3, then the sum of all possible (q) 175 value of x + y will be If N is divisible by 6, then number of orded pairs (x, y) can be If N is divisible by 9, then the sum of possible value of x + y will be (C)

Solution