Question

Sol. (3) Relative speed ( =(84+6) mathrm{kmph}=90 mathrm{kmph} )
( =left(90 times frac{5}{18}right) mathrm{m} / mathrm{sec} )
( =25 mathrm{m} / mathrm{sec} )
( therefore ) Length of train ( = ) Relative speed ( times ) Time ( =25 times 4=100 ) metre

# mning at the speed of 84 km/hr pass- valking in opposite direction at the Ez.1. A train running at the speed o es a man walking in opposite direc speed of 6 km/hr in 4 seconds. What is the length of train (in metre) ? SSC CGL Tier-I 2014 (1) 150 (2) 120 (3) 100 (4) 90

Solution