N 52-17 1-1 -8 -107 t| 1 0A= 1-2 -5...
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# N 52-17 1-1 -8 -107 t| 1 0A= 1-2 -5. 1-3 4] [922 15] -

Railway Exams
Maths
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( left[begin{array}{cc|cc|ccc}2 & -1 & & & 1 & 8 & 10 1 & 0 & x+1 & 0 & 1 & -2 & 5 -3 & 4 & & 0 & 0 & 0 & 15end{array}right] ) ( (sin 2 x cos x)^{2}=left(3 x^{3}right) ) ( m ) ( A=(2 times 3) ) mabing ( =left[begin{array}{lll}x_{1} & y_{1} & 3_{1} x_{2} & y_{2} & y_{2}end{array}right] ) ( left[begin{array}{cc}2 & -1 1 & 0 -3 & 4end{array}right] eqleft[begin{array}{ccc}x_{1} & y_{1} & x_{1} x_{2} & y_{2} & 3end{array}right] quadleft[begin{array}{ccc}1 & -8 & -10 1 & -2 & -5 a & 22 & 15end{array}right] ) ( left[begin{array}{ccc}2 x_{1}-x_{2} & 2 y_{1}-y_{2} & 2 x_{1}-3 x_{1} & y_{1} & 3_{1} -3 x_{1}+4 x_{2} & -3 y_{1}+4 y_{2} & -3 z_{1}+43end{array}right]-left[begin{array}{ccc}1 & -8 & 10 1 & -2 & -5 9 & 22 & 15end{array}right] ) By equaling ( left|x_{1}=1 intright| y_{1}=-||2 3_{1}=-5 mid ) ( 2[1]-x_{2}=-1 quad 2 y_{1}-y_{2}=-8 quad 23,1-3, x-k ) ( A=left[begin{array}{rrr}1 & -2 & -5 3 & 4 & 0end{array}right]left[begin{array}{lll}x_{2}-3 & -4 & -y_{2}-8 & 2[-5]-3,0-10 & & {[y=4} & -10-3 & & 3end{array}right] ) "