Question

( frac{h_{f}}{lambda}=frac{b_{1}}{lambda_{1}}+frac{h_{2}}{lambda_{2}} )
( frac{1}{400}=frac{1}{500}+frac{1}{x} )
( frac{-1}{x}=frac{1}{500}-frac{1}{400}=frac{4-5}{2000} )
( frac{1}{x}=frac{1}{2000} Rightarrow lambda=2000 mathrm{mm} )

# ns. One (C) wave Hume WILT U die A photon of 400 nm is absorbed by a gas molecule and then the molecule re-emits two photons re-emitted photon has wavelength 500 nm. Assuming that there is no change in the energy of mole the wavelength of second re-emitted photon is (A) 100 nm (B) 2000 nm (C)-100 nm (D) 900 nm

Solution