Question

Melewilas formula of Pofash Alum
[
=k_{2} S O_{4} cdot A l_{2}left(S O_{4}right)_{3} cdot 24 M_{2} O
]
( n_{f}= ) Total no. of charges fotash ACum has ( 2 mathrm{k} ) uons resulling
( =8 )
in total of ( 2 x 1+2 times 3 )
[
begin{array}{l}
=8 text { the chacges }
therefore quad 4 n=8
end{array}
]
Mol formula of gypsmm
V)
[
operatorname{cas} 0, frac{1}{2} mathrm{h}_{2}
]
( n_{f}= ) Total charges [ =1 text { la ion thal } 180 text { n isen } ] ( =2 ) chargen
[
begin{array}{l}
n_{f}=2
e_{q} cdot w t=frac{m o l cdot u t}{n_{f}}=frac{M_{1}}{x}[text { for notash }]
text { alum }
end{array}
]
( =frac{m_{1}}{y}left[f_{0} g_{y} sin nright] )
[
begin{array}{l}
Rightarrow x=8, y=2
Rightarrow x-y=8-2=6
end{array}
]

# Number of lone pairs in 18 ml H,O at 273 K IS XNA. The value UI WII U 5. Equivalent weight of Pottash alum is and equivalent weight of gypsum is . Then x - y will be 6. An Oleum is labelled as 105% Then 100 g of this Oleum will react with y gram of water. What will be value ofiel

Solution