Number of lone pairs in 18 ml H,O a...
Question

# Number of lone pairs in 18 ml H,O at 273 K IS XNA. The value UI WII U 5. Equivalent weight of Pottash alum is and equivalent weight of gypsum is . Then x - y will be 6. An Oleum is labelled as 105% Then 100 g of this Oleum will react with y gram of water. What will be value ofiel

JEE/Engineering Exams
Chemistry
Solution
83
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Melewilas formula of Pofash Alum [ =k_{2} S O_{4} cdot A l_{2}left(S O_{4}right)_{3} cdot 24 M_{2} O ] ( n_{f}= ) Total no. of charges fotash ACum has ( 2 mathrm{k} ) uons resulling ( =8 ) in total of ( 2 x 1+2 times 3 ) [ begin{array}{l} =8 text { the chacges } therefore quad 4 n=8 end{array} ] Mol formula of gypsmm V) [ operatorname{cas} 0, frac{1}{2} mathrm{h}_{2} ] ( n_{f}= ) Total charges [ =1 text { la ion thal } 180 text { n isen } ] ( =2 ) chargen [ begin{array}{l} n_{f}=2 e_{q} cdot w t=frac{m o l cdot u t}{n_{f}}=frac{M_{1}}{x}[text { for notash }] text { alum } end{array} ] ( =frac{m_{1}}{y}left[f_{0} g_{y} sin nright] ) [ begin{array}{l} Rightarrow x=8, y=2 Rightarrow x-y=8-2=6 end{array} ]