Question

o 89. What is the de-Broglie wavelength associated with the hydrogen electron in its third orbit :-

NEET/Medical Exams

Chemistry

Solution

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Radius of ( 3 mathrm{rd} ) orbit ( =mathrm{r}=mathrm{R}(3)^{wedge} 2 ) ( =9 mathrm{R} ) [Here ( mathrm{R}= ) Radius of first orbit of hydrogen atom] ( mathrm{mvr}=mathrm{nh} /(2 mathrm{m}) ) ( mathrm{h} /(mathrm{mv})=2 pi r / mathrm{n} ) ( lambda=h /(m v)=2 pi times 9 R / 3 ) ( lambda=6 pi mathrm{R} ) ( lambda=6 pi times(0.529 AA) ) ( lambda=9.97 AA ) De-Broglie wavelength is 9.97 ( A )