Question

Radius of ( 3 mathrm{rd} ) orbit ( =mathrm{r}=mathrm{R}(3)^{wedge} 2 )
( =9 mathrm{R} )
[Here ( mathrm{R}= ) Radius of first orbit of
hydrogen atom]
( mathrm{mvr}=mathrm{nh} /(2 mathrm{m}) )
( mathrm{h} /(mathrm{mv})=2 pi r / mathrm{n} )
( lambda=h /(m v)=2 pi times 9 R / 3 )
( lambda=6 pi mathrm{R} )
( lambda=6 pi times(0.529 AA) )
( lambda=9.97 AA )
De-Broglie wavelength is 9.97
( A )

# o 89. What is the de-Broglie wavelength associated with the hydrogen electron in its third orbit :-

Solution