Question

Let resstance before steetching be ( R_{1}=10 Omega ) The Founula of remstarce is ( R=k frac{L}{A} ) L = Length of remitance A theien of consection ( v= ) Volume of wrise It in comtant ( V=A ) A ( x L )
( Rightarrow A=underline{V} )
[
begin{array}{l}
therefore R_{1}=kleft(frac{L^{2}}{v}right)
text { Aflee cliet thing length becomes }
(L+0 cdot 25 L)=1.25 L
end{array}
]
Now rens
[
begin{array}{l}
qquad begin{array}{c}
R_{2}=kleft(frac{(1 cdot 25 L)^{2}}{V}right)
R_{1}=frac{K(1 cdot 25)^{2} k^{2}}{X}=(1.25)^{2}
frac{R_{2}}{R_{1}}=1.5625
end{array}
end{array}
]
( begin{aligned} R_{2} &=1 cdot 5625 times R_{1} &=1.5625 times 10 &=15.625 Omega end{aligned} )

# o wire is 10 S2. Its length is 12. The resistance of a 10 m long wire is 10 . It increased by 25% by stretching the wire uniformly. The resistance of wire will change to (approximately) (a) 12.5 12 (b) 14.522 (c)15.612 (d) 16.622

Solution