Obtain all zeroes of x4-3x3-7x2 +9x...
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Obtain all zeroes of x4-3x3-7x2 +9x +12 iftwo of its zeroes are + V3.Sum of zeroes is

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Maths
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( pm sqrt{3} ) are zeroes ( Rightarrow(x+sqrt{3})(x-sqrt{3})=x^{2}-3 ) is a divisor of ( x^{4}-3 x^{3}-7 x^{2}+9 x+12 ) [ begin{aligned} q(x) &=x^{2}-3 x-4=x^{2}-4 x+x-4 &=x(x-4)+1(x-4) q(x) &=(x+1)(x-4) end{aligned} ] zeroes of ( q(x) ) are -1,4 ( therefore ) Remaining required zeroes are -1,4 Sum ( =-1+4=3 )
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