On a new scale of temperature (whic...
Question

On a new scale of temperature (which is linear) and called the ( W ) scale, the freezing and boiling points of water are ( 39^{circ} mathrm{W} ) mol ( 239^{circ} mathrm{W} ) respectively. What will be the temperature on the new scale, corresponding to a temperature of ( 39^{circ} mathrm{C} ) on the Celsius scale?1 ( 78^{circ} mathrm{W} )2. (117^{circ} mathrm{W} )3. (200^{circ} mathrm{W} )4. ( 139^{circ} mathrm{W} )

JEE/Engineering Exams
Physics
Solution
50
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B. ( 117^{circ} mathrm{C} )
In general, whenever we are to go from any known scale to any unknown scale, then we follow the equation
(temperature on known scale) - (LFP for known scale)
(UFP - LFP ) Known (temerature on unknown scale)
( =-( ) LEP for unknown scale ( ) )
(UFP-LFP) unknown
or ( frac{390-0}{100-0}=frac{t-39}{239-39} )
( t=117^{circ} mathrm{W} )
LFP = Lower fixed point UFP = Upper fixed point

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