One ne mole of monoatomic ideal gas...
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One ne mole of monoatomic ideal gas expands adiabatically at initial temp. T against a constant external pressure of 1 atm from one litre to two litre. Find out the final temperature. (R = 0.0821 litre. atm K-moll) (JEE Adv. 2005] (A) T (C) T- (2) 3x0.0821 (D) T+ 0 3x0.0821

JEE/Engineering Exams
Chemistry
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monoatomic gas Adiabatic Process Pext ( =operatorname{lam}_{1} T_{1}=1 L V_{2}=2 L ) ( T_{1}=T quad T_{2}=? ) ( T V^{gamma-1}= ) Constant ( T_{1} V_{1}^{gamma-1}=T_{2} V_{2}^{gamma-1} ) ( T_{2}=T_{1}left(frac{V_{1}}{V_{2}}right)^{gamma-1} ) ( =Tleft(frac{1}{2}right)^{r-1} ) ( =frac{T}{2 gamma-1}=frac{T}{2^{5} 13-1}(B) )
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