Question

OU The value of (0.16)|(92.5 0.25 is (A) 2.5 (B) 8 (C) 16

JEE/Engineering Exams

Maths

Solution

225

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tet ( y=(0.16)^{log _{2.5} 25} ) ( log y=frac{log _{0.25}}{log _{2.5}} log _{0.16} ) ( =frac{-2 log _{2}}{log 5-operatorname{tog}_{2}} cdot frac{-2 mid log 5-log 2)}{=4 log 2} ) ( y=2^{4}=16 )