Question

tet ( y=(0.16)^{log _{2.5} 25} )
( log y=frac{log _{0.25}}{log _{2.5}} log _{0.16} )
( =frac{-2 log _{2}}{log 5-operatorname{tog}_{2}} cdot frac{-2 mid log 5-log 2)}{=4 log 2} )
( y=2^{4}=16 )

# OU The value of (0.16)|(92.5 0.25 is (A) 2.5 (B) 8 (C) 16

Solution