paq is logically equivalent to : (a) p-97 (b) 9 →pa tey (p 9) (d) ~(9 →p)

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begin{tabular}{c|c|c|c|c|c} ( p ) & ( q ) & ( sim p ) & ( sim p_{1} q ) & ( q^{prime} rightarrow p ) & ( sim(q-p) ) hline( T ) & ( F ) & ( f ) & ( F ) & ( T ) & ( F ) ( T ) & ( F ) & ( F ) & ( F ) & ( T ) & ( F ) ( F ) & ( T ) & ( T ) & 7 & ( F ) & ( T ) ( F ) & ( F ) & ( T ) & ( F ) & ( T ) & ( F ) hline end{tabular}

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