Percentage of Se in peroxidase enzy...
Question
Percentage of Se in peroxidase enzyme is 0.5% by weight (Se=78.4). Then the minimum molecular weight of peroxidase enzyme is
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Percentage of Se in peroxidase enzyme is ( 0.5 % ) by weight ( (mathrm{Se}=78.4) ). Then the minimum molecular weight of peroxidase enzyme is
(1) ( 3.13 times 10^{4} )
( begin{array}{ll}text { (2) } & 15.68end{array} )
(3) ( 1.568 times 10^{3} )
( begin{array}{ll}text { (4) } 1.568 times 10^{4} & text { 4 }end{array} )

JEE/Engineering Exams
Chemistry
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Percentage of Se in peroxidase enzyme is 0.5% by weight (Se=78.4). Then the minimum molecular weight of peroxidase enzyme is
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Minimum molecular weight of peroxidase anhydrous enzyme is ( 15,792 mathrm{g} / mathrm{mol} ).
Explanation:
Let the molar mass of the peroxidase anhydrous be M
One molecule of peroxidase anhydrous contain 1 atom of Se
( 0.5 %=frac{78.96 g / m o l}{M} times 100 )
( M=frac{78.96 mathrm{g} / mathrm{mol}}{0.5} times 100=15,792 mathrm{g} / mathrm{mol} )
Minimum molecular weight of peroxidase anhydrous enzyme is ( 15,792 mathrm{g} / mathrm{mol} )

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