Question
We have
( sin theta=n sin (theta+2 alpha) )
( Rightarrow frac{sin (theta+2 alpha)}{sin theta}=frac{1}{n} )
( Rightarrow frac{sin (theta+2 alpha)+sin theta}{sin (theta+2 alpha)-sin theta} )
( Rightarrow frac{1+n}{1-n} )
( Rightarrow frac{2 sin (theta+alpha) cdot cos alpha}{2 sin alpha cos (theta+alpha)}=frac{1+n}{1-n} )
( tan (theta+alpha)=frac{1+n}{1-n} tan alpha )
Hence (d) is the correct option.

PINNACLE Jwuy Material P-1921-P1-CBSE-MA-TRI-24 n If sino = nsin(0+20) then tan(0+ o) is equal to (A) + ntana (B)- tana ( 1+nar 2-n (0) 1+tana (C) tana
Solution
