Question

Prove that in a triangle ABC, sin Asin(B-C)= 0.

JEE/Engineering Exams

Maths

Solution

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( sum sin A sin (B-c)=0 ) on ( Delta A B C ) ( A+B+C=pi ) ( A=pi-(B+C) ) ( sum sin (B+C) sin (B-C) ) ( =sum_{S 17}left(31 n^{2} B-operatorname{Sin}^{2} Cright) ) ( =0 ) ( therefore ) Hence Proved