Question

Prupul LULIS. 8. (1) 10 g of lead on heating gave 10.78 g of litharge, PbO. (ii) 9.775 g of red lead (Pb202) yielded on strong heating 9.545 g of litharge. (iii) 4.87 g of lead peroxide (PbO2) gave on heating 4.545 g of litharge. Show that these results illustrate the law of multiple proportions.

JEE/Engineering Exams

Chemistry

Solution

318

2.0 (2 ratings)

i) wrive litharge ( 2 quad(0.789) ) wt ( cdot ) of ( operatorname{leg} d^{circ}=10 mathrm{g} ) Whint oxegen 789 in litharge wt of oxygen that combines with I g of lead = 0.078 Similarly, ii) wt of oxy glen in 9.775 g of red lead? ( (9 cdot 775-8 cdot 854)=0.921 g ) ( therefore 18 ) OF Pb in combination with [ 0.921 / 8 cdot 854=0.104 g ] Wi ( > ) Similarly [ infty t cdot 0,0,2,1 n<4 cdot 87,90,0,150 ] ( Rightarrow 4 cdot 87-4 cdot 216=0 cdot 654902 ) ( therefore ) i g of lead in Pbo cosn bineswith [ 0 cdot 654 / 4 cdot 216=0 % 5390002 ] The ratio of 0,2 thret com lines with If ( P b ) in ( P b 0 ), red. Rend & lead peroxide i 8 [ 0.078: 0.104: 0.155 ] ( 1: frac{4}{3}: 20 r ) 3: 4: 6 5 This shows the lano of muldiple Proportiong