Question

# Q.1 Number of digits in 416.525 is (use log,.2=0.3010) see (A)27 (B) 28 (C)29 (D) 30

Solution

${4}^{16}.{5}^{25}\phantom{\rule{0ex}{0ex}}\mathrm{Apply}\mathrm{log}.\phantom{\rule{0ex}{0ex}}\mathrm{log}({4}^{16}.{5}^{25})\phantom{\rule{0ex}{0ex}}\mathrm{log}{4}^{16}.+\mathrm{log}{5}^{25}\phantom{\rule{0ex}{0ex}}\mathrm{log}{(2}^{}$