Q.10(a) Let a and B be the roots of x2 - 6x-2=0, with a > B. If a = " -B" for n?! le value of 210 – 2ag is 2a9 (4) (B)2 (C) 3 (D) 4

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( x^{2}-6 x-2=0 ) ( x=frac{6 pm sqrt{36+8}}{2} ) ( =6 pm sqrt{44} ) ( alpha_{1} beta ) ale xoots of ( x^{2}-6 x-2=0 ) since ( alpha(B text { are } operatorname{soc} t) ) of ( n^{2}-6 n-2 ) ( x^{2}-6 x+2=0 ) ( begin{aligned} alpha^{2}-2=6 alpha & text { similarly } beta^{2}-2=6 beta =&=frac{6left[alpha^{9}-beta^{2}right]}{2left[alpha^{9} beta^{9}right]} &=3 end{aligned} )

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