Question

( frac{1-cos u alpha}{sec ^{2} 2 alpha-1}+frac{1+cos 4 alpha}{operatorname{cosec}^{2} 2 alpha-1} )
( 1-cos u alpha=2 sin ^{2} 2 alpha )
( 1+cos u=2 cos ^{2} 2 alpha )
( frac{2 sin ^{2} 2 alpha}{sec ^{2} 2 alpha-1}+frac{2 cos ^{2} 2 alpha}{operatorname{cosec}^{2} 2 alpha-1} )
( Rightarrow quad 2 sin ^{2} 2 alpha operatorname{cosec}^{2} 2 alpha-2 sin ^{2} 2 alpha+2 cos ^{2} 2 alpha sec ^{2} 2 )

# Q.17 is equal to 1 - cos 4a 1 + cos 4a sec? 2a -1 cosec 2a - 1 (A) 0 (B) 2 (C1 (D) 4

Solution