The set of values of p for which(p ...
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The set of values of p for which(p - 2)x^2 + 7x + p^2 - 4p = 0 has roots of opposite signs are

(A) 0<p<2

(B) 2<p<4

(C) p<0

(D) 0<p<4

JEE/Engineering Exams
Maths
Solution
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The set of values of p for which(p - 2)x^2 + 7x + p^2 - 4p = 0 has roots of opposite signs are
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(p-2)x2+7x+p2=4p       -α                                                - β given     αβ<0       p2-4pp-2<0      p(p-4)p-2<0   p<0 and 2<p<4   Ans.- B,C

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