Question

Q.2 .: x² +38-4 Ifx is real then find the range of y=- x? +7x +12

JEE/Engineering Exams

Maths

Solution

230

4.0 (1 ratings)

( y=frac{x^{2}+3 x-4}{x^{2}+7 x+12}, x in R ) ( y=x^{2}+4 x-x-4 ) ( x^{2}+3 x+4 x+12 ) ( y=(x+4)(x-1) ) ( (x+3)(x+4) ) ( x eq-3,-4 ) as denominater cannot be 0 ans ( x in(-infty,-3) cup(-3,-4) cup(-4, infty) )