Q.22 the If the roots of the equation, 33 +Px2 + Qx-19=0 are each one more than the roots of the equation #3 - Ax2 + Bx – C = 0, where A, B, C, P & Q are constants then the value of A+B+C = (A) 18 (B) 19 (C) 20 (D) None of these

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( x^{3}-a x^{2}+b x-c=0 ) Whits root be ( alpha, beta, r ) ( alpha+beta+gamma=-frac{(-a)}{1}=a-0 ) ( alpha beta+beta gamma+alpha gamma=b ) ( alpha beta gamma=c ) Au to question, rusis of ( operatorname{cgm} x^{3}+p x^{2}+q-19=0 ) ( operatorname{arc}(alpha+1),(beta+1) operatorname{ard}(gamma+1) ) as in the abone example ( Rightarrow a+b+c=19-1 ) ( 2 a+b+c=18 )

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