Q.26 cos 24° + cos 5° + cos 175° + ...
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Q.26 cos 24° + cos 5° + cos 175° + cos 204° + cos 300° = 1 (B) - (D) 1.

JEE/Engineering Exams
Maths
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(18) ( cos (180-x)=-cos (x) ) (2) ( cos (175)=-cos (5) ) (x) ( cos 24+cos 5+cos 175+frac{1}{12} cos 204+cos 30 ) ( =1 / 2 )
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