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Q.4 Given that ax2 + bx + c = 0 has...
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Q.4 Given that ax2 + bx + c = 0 has no real roots and a + b +c<0, then - (A) c = 0 (B) c>0 (C) c< 0 (D) None
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No real noots ( Rightarrow quad b^{2}-4 a c<0 ) [ begin{array}{l} quad x quad b^{2} / 4
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