Q.5, If the function f(x)= x?+e2 and g(x)=f'(x), then the value of g'(1) is

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( 1 ) and g are muede of each other ble Hen [ g^{prime}(f(x, 1))=frac{1}{f^{prime}(x)} ] So to frid g ( ^{prime}(1) ) and reed ( f(x)=1 ) at ( x=0 ) [ g^{prime}(1)=frac{1}{f^{prime}(0)}=frac{1}{3 x^{2}+frac{1}{2} e^{x / 2}} cdot 9+x=0 ]

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