Question

( F_{k}+w=h v_{1}-0, v_{1}=2.5 times 10^{16}+1 z )
( 2 E_{k}+w=h v_{2}-0, v_{2}=4 times 10^{16} mathrm{Hz} )
ó ( W=8 hleft(2 v_{1}-v_{2}right) )
( =h(5-4) times 10^{16} mathrm{J} )
( =6.62 times 10^{-3.4} cdot h times 10^{16} 5 )
Threshold frequenty, ( v_{0}=frac{11}{h}=10^{16} mathrm{Hz} )

# Q-6 If a light with frequency 4 x 1016 Hz emitted photoelectrons with double the kinetic energy as are emitted by the light of frequency 2.5 x 1016 Hz from the same metal surface, then what is the threshold frequency (no) of the metal ?

Solution