Question

[
begin{aligned}
cos A=-3 / 5 &, quad operatorname{ar} A=sqrt{1-cos ^{2} A}=frac{4}{5}
therefore tan A &=frac{sin A}{cos A}=frac{-4}{3}
end{aligned}
]
The equation is :
( Rightarrow quad x^{2}-(sin A+tan A) times+[sin A cdot tan A)=0 )
[
begin{array}{r}
x^{2}-left(-frac{8}{15}right) x+left(frac{-16}{15}right)=6
15 x^{2}+8 x-16=0
end{array}
]
?

# Q.6 In a triangle ABC, the value of ZA is given by 5 cosA + 3 = 0, then the equation whose roots are sin A and tan A will be

Solution