Question

( x^{2}+4 y^{2}-4 x y+4 y-2 x-8 )
By ( quad(a-b)^{2}=a^{2}+b^{2}-2 a b )
Here.
( (x-2 y)^{2}+4 y-2 x-8 )
( (x-2 y)^{2}+2(2 y-x-4) )

# Q.63 The factors of (x2 + 4y2 + 4y - 4xy -- 2x - 8) are- Q.72 DY

Solution

Instasolv

Solution