Question

( Rightarrow ) given equr ( (k-2) x+4 y=10 )
[
begin{array}{c}
x=2 quad y=1
(k-2) begin{array}{c}
2+4=10
2 x-4+y=10
end{array}
therefore k=5
end{array}
]
Go-ordinate of the pt. where the graph wis the y-axis is
D) ( p^{+}+(2,1) )

# Q1: Topic: Linear Equation in Two Variables Find the value of K if x=2 and y=1 is a solution of the equation (K-2) x + 4y = 10 and have the graph of the equation. Write the co-ordinate of the point where the graph cuts the y-axis.

Solution