Question

( frac{theta v-9}{r i n d}+b x^{2}+frac{1}{x^{2}}=38 rightarrow 0 )
O) ( quad sin left(x-frac{1}{x}right)^{2}=x^{2}+frac{1}{x^{2}}-2 cdot x cdot frac{1}{x} )
( Rightarrowleft(x-frac{1}{x}right)=sqrt{38-2}(6000) )
( Rightarrowleft(x+frac{1}{x}right)=sqrt{36} )
( Rightarrowleft(x+frac{1}{x}right)=pm 6 )

# Q8 Q9 Q10 If ax + bx² + x - 6 has (x + 2) as a factor and leaves a remainder 4 when divided by (x - 2), find the values of a & b. If (x2 +1/x2) = 38, the find the value of (x - 1/x) If both (x - 2) and (x - 12) are the factors of px + 5x+r, show that p=r

Solution