Question

quadratic equation 0.20 If a, ß are the root of a quadratie + 5 = 0 then the equation whose roots are (Q2 - 3a + 7) and (B2 – 3B + 7) is. (4) x2 + 4x+1=0 (B) x2 - 4x + 4 = 0 (C) x2 - 4x-1=0 (1) 2 + 2x + 3 = 0

JEE/Engineering Exams

Maths

Solution

120

4.0 (1 ratings)

2 ( alpha^{2}-3 alpha+7^{2} quad(alpha-3 alpha+5)+2 ) 22 ( p^{2}-3 beta+7=frac{6^{2}-3 x+2+2}{2} ) as ( beta ) is a fector [ 2 text { . } ] ( 8 x-4 x^{2}-4 x+4=0 )