Question

2
( alpha^{2}-3 alpha+7^{2} quad(alpha-3 alpha+5)+2 )
22
( p^{2}-3 beta+7=frac{6^{2}-3 x+2+2}{2} ) as ( beta ) is a fector
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( 8 x-4 x^{2}-4 x+4=0 )

# quadratic equation 0.20 If a, ß are the root of a quadratie + 5 = 0 then the equation whose roots are (Q2 - 3a + 7) and (B2 – 3B + 7) is. (4) x2 + 4x+1=0 (B) x2 - 4x + 4 = 0 (C) x2 - 4x-1=0 (1) 2 + 2x + 3 = 0

Solution