Question

From ( A ) to ( C ), Energy ( =12400 / 3000=4.13 mathrm{eV} )
From ( B ) to ( C ), Energy ( =12400 / 6000=2.1 mathrm{eV} )
Now, if we subtract the second equation from the first, we'll get the energy of the electron when it jumps from ( A ) to ( B ). So, Energy ( =4.13-2.1 mathrm{eV}=2.03=2 mathrm{eV} )
Therefore, Wavelength ( =12400 / 2 ) Angstorm ( = ) (around 6000 Angstorm)

# r's Atomic model & Spectrum Wavelength of radiations emitted when an electron jumps from a state A to Cis 2000 Å and it is 6000 Å when the electron jurnps from state B to state C. Wavelength of the radiations emitted when an electron jumps from state A to B will be (A) 2000 Å (B) 3000 Å (C) 4000 Å (D) 6000 À

Solution