Range of f(x) = cos"( Vx2+x+1) is
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Range of f(x) = cos"( Vx2+x+1) is

JEE/Engineering Exams
Maths
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( f(x)=cos ^{-1}(sqrt{x^{2}+x+1}) ) For ronge of ( sqrt{x^{2}+x+1} ) root of ( x^{2}+u+1=frac{-1 pm sqrt{1-4}}{2} eq ) ingrinay they ( x^{2}+4+1 in[3 / 4, infty) ) ( therefore sqrt{x^{2}+x+1} inleft[frac{sqrt{3}}{2}, inftyright) ) ( therefore cos ^{-1}(sqrt{x^{2}+x+1}) in[0, pi / 6] ) ( a t x=frac{-b}{2 a}=frac{-1}{2} ) ( f(x)=(3 / 4) )
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