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Read the following passage and answer the questions that follow. Let ABCD be a parallelogram the equation of whose dia parallelogram the equation of whose diagonals are AC:X + 2y = 3; BD: 2x + y = 3.14 length of diagonal AC = 4 units and area of ABCD = 8 sq. units. The length of other diagonal BD is (B) 20 (D) 5 (C) 2 The length of side AB is equal to 5. (A) 2158 3 (B) 2458 (C) 3/58 (D) 4V58

JEE/Engineering Exams
Maths
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( A C=x+2 y=3 ) ( B D=2 x+y=3 . .6 ) 3) Solving 4 ii We get o(1.1). ( m= ) Ar. of ( 11 mathrm{g} ) binu Doth diayonal are Equol. So it is c squari, Rhombur or rectayle. ( = ) SIUH IT ( A C=frac{-1}{2}[because y=m times+. C] ) ( f ) blope ( 7 B D= ) ( f_{1} x m_{2}=+1 ) ( therefore ) phothect of ( s ) lom ( eq-1 ) if isnot square or Rhombung ( therefore A D C D ) is Rectayth. ( Rightarrow quad a^{2}+b^{2}=4^{2}=16 ) ( a^{2}+frac{64}{a^{2}}=16 )( quad a times b=8 ) ( b=8 / a ) :) ( a^{4}+64-16 a^{2}=0 ) ( Rightarrowleft(a^{2}-8right)^{2}=frac{a-1 a^{2}=8}{sqrt{a}=2 sqrt{2}} ) ( operatorname{sen} sqrt{13-2 sqrt{2}} )
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