Question # Rearrange the following ( I to IV) in the order of increasing masses.
(1) 0.5 mole of Og
((II) 6.5 gm molecûle of Nitrogen
(III) 3.011 1023 molecule of O,
(IV) 11.35 L of Co, at STP
02-
(A) IV < III < II

# Rearrange the following ( I to IV) in the order of increasing masses.
(1) 0.5 mole of Og
((II) 6.5 gm molecûle of Nitrogen
(III) 3.011 1023 molecule of O,
(IV) 11.35 L of Co, at STP
02-
(A) IV < III < II * *

Solution 5) ( 0.0 cdot 5 ) mole ( f cdot 0.3 equiv 0.5 times(16 times 3)(2 times 0.0) )
[
begin{array}{l}
=frac{1}{2} times 48 text { potet } g
=24 mathrm{g}
end{array}
]
(2) 0.5 gean motecule ( r ). ( n ) itrogen [ 11 / 1 ] equivalent
3
( =frac{1}{2} x(16 times 2) g )
( =169 )
( therefore 0, operatorname{tin} n cdot(B) )
( =frac{1}{2} times 44 g=229 )

Solution