respectively and the CF کا رو رو کن...
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respectively and the CF کا رو رو کن دانلود عطا

JEE/Engineering Exams
Physics
Solution
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Given ( bar{A}+bar{B}=bar{C} ) Squaring on both sides we get ( bar{A}^{2}+bar{B}^{2}+2 bar{A} bar{B}=bar{C}^{2} ) ( Rightarrow(12)^{2}+(5)^{2}+2 bar{A} bar{B}=(13)^{2} ) ( Rightarrow 144+25+2 bar{A} bar{B}=169 ) ( Rightarrow 169+2 bar{A} bar{B}=169 ) ( Rightarrow 2 bar{A} bar{B}=0 ) ( Rightarrow bar{A} bar{B}=0 ) Let be the angle between ( A ) and ( B ). ( cos theta=frac{bar{A} bar{B}}{bar{A}^{2}+bar{B}^{2}} ) ( Rightarrow cos theta=0 ) ( therefore ) Angle between ( A ) and ( B ) is ( 90^{0} )
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