Question

(0) ( quad x^{2}+b x+b=0 )
Let the roots of above equation be ( alpha, beta ). Since ( x^{2}+b x+b ) is a factor of ( x^{3}+2 x^{2}+2 x+c ), so
the roots of ( x^{3}+2 x^{2}+2 x+c ) be also ( alpha ), ( beta ). Lel other
100t be r.
( alpha beta=bleft[text { as in eq }^{n} ) is right.
(Tii)

# RO Basic Equations and Inequality (Linear Equation and Inequation, Poly 2+bx+b is a factor of x + 2x2 + 2x +(c +0), then b-cis a inequation, Polynomials) 15. If x² + bx (A) 2 (B)-1 (CO (D) -2

Solution