Question

( x^{3}-22 x^{2}+142 x-120 )
Let ( p(x)=x^{3}-2 x^{2}+142 x-120 )
sherting ( p(x)=0 )
[
x^{3}
]
Note The term ehould be ( 23 x^{2} ) and -120
Co, colving ( x^{3}-23 x^{2}+142 x-120 ) ( begin{aligned} & x^{3}-x^{2}-22 x^{2}+22 x+120 x+120 =& x^{2}(x-1)-22(x-1)+120(x-1) =&(x-1)left(x^{2}-22 x+120right) =&(x-1)left(x^{2}-12 x-10 x+120right) =&(x-1)(x(x-12)-10(x-12)) =&(x-1)(x-10)(x-12) end{aligned} )

# S. No. Date Title Page No. Teacher's Sign/Remarks Fact Coriser le 3-22264+14200-120

Solution