sation Find value of log2. 1993 1994-

Solution

Share

119

4.0 (1 ratings)

Download App for Answer

( A=log _{2} log _{2} log _{4} 256+2 log _{sqrt{2}} 2 ) ( A=log _{2} log _{2} log _{4} 4^{4}+2 log _{(2) 1 / 2} 2^{2} ) ( A=log _{2} log _{2}left(4 times frac{left.log _{4} 4right)}{4}+frac{2}{1 / 2} log _{2} 2right. ) ( A=log _{2} log _{2} 4+4 times 1 ) ( A=log _{2} log _{2}(2)^{2}+4 times 1 ) ( A=log _{2}left(2 times log _{2} 2right)+4 ) ( A=log _{2} 2+4 ) ( A=1+4=5 )

119

4.0 (1 ratings)

Rate Solution

Share