Question

( theta I=int_{0}^{pi / 2} frac{sin ^{2} x d x}{1+sin x cos x} )
( widehat{N}=int_{0}^{q} f(x) d x=int_{0}^{a} f(a-x) d x rightarrow operatorname{Rop} )
( Rightarrow quad Omega=int_{0}^{1 / 2} frac{sin ^{2}left(frac{pi}{2}-xright)}{1+sin left(frac{pi}{2}-xright) cos left(frac{pi}{2}-xright)^{2}} )
5

# sin²x Ñ 12. - dx =- • 1+ sin x cos X 313

Solution