Question
( frac{sin theta}{1+cos theta}+frac{(1+cos theta)}{sin theta}=operatorname{cosec} theta )
( begin{aligned} sin ^{2} theta+(1+cos theta)^{2} &(1+cos theta) sin theta =& sin ^{2} theta+v+cos ^{2} theta+2 cos theta (1+cos theta) sin theta &=(1+cos theta) sin theta =& frac{2(1+cos theta)}{(1+cos theta) cdot sin theta)} =& 2 cos 2 theta theta cdot A end{aligned} )

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Solution
